Lesson 6 of 35 · Quantitative Reasoning: arithmetic
Statistics for Quant: averages, medians and spread
Work with sums instead of averages, find medians, handle weighted and evenly spaced sets, and judge standard deviation without computing it.
About 20 minutes
In this lesson
- Solve mean questions through the sum, including values added or removed.
- Find a weighted average, a median and the mean of an evenly spaced set quickly.
- Predict how changes to a set affect its standard deviation without calculating it.
- Find the largest or smallest possible value under a fixed mean and median.
The idea
Think in sums
The mean of a list is its sum divided by the number of values, so
Almost every averages question becomes easy once you switch from means to sums. If five numbers average 18, they add to 90. If a sixth number lifts the average to 20, the six add to 120, so the new number is . A second way to see the same thing: the new number must equal the new mean (20) plus enough to lift each of the five old numbers by 2, that is .
Weighted averages
When groups of different sizes are combined, the overall mean is a weighted average:
It lies between the two group means, closer to the larger group. The balance method from mixtures applies: the distances from the overall mean to the group means are in the inverse ratio of the group sizes. Averaging the two means directly is right only when the groups are the same size.
Median, mode and range
The median is the middle value once the list is sorted. With an even number of values it is the mean of the two middle values. The median ignores how far the extreme values are from the middle, so one huge value moves the mean but not the median. The mode is the most frequent value (a list can have several). The range is the largest value minus the smallest.
Evenly spaced sets
In a list with a constant gap between consecutive values (consecutive integers, consecutive multiples of 5, and so on), the mean equals the median, and both equal the average of the first and last values:
The number of values is ; forgetting the is the usual off-by-one slip. The sum is the number of values times the mean, so the integers from 11 to 40 add to .
Standard deviation without computing it
Standard deviation measures how far the values typically lie from the mean. You will rarely need to compute it; you need to know how it reacts:
| Change to every value | Effect on the standard deviation |
|---|---|
| add or subtract the same constant | none: the values move together |
| multiply by | multiplied by |
| add a new value equal to the mean | decreases (unless it is already 0) |
| add a new value far from the mean | increases |
To compare two sets, compare the distances of their values from their own means. and have the same standard deviation; has twice as much as either.
Extremes under constraints
"What is the greatest possible value of the largest number?" asks you to make every other number as small as the conditions allow, and then let the sum do the rest. Read every condition: whether the numbers must be different, positive, integers, and where the median sits.
Worked examples
Example 1: Finding a removed value
The mean of eight numbers is 15. When one number is removed, the mean of the remaining seven is 14. What number was removed?
Switch to sums: the eight numbers add to and the seven add to .
The removed number is .
Check another way: removing a value above the mean pulls the mean down. Each of the seven remaining values "gave" 1 to cover the drop, so the removed value was .
Answer
The removed number is 22. Answering 1, the change in the mean, is the quick misreading.
Example 2: Mean of two classes
A class of 20 students has a mean score of 72, and a class of 30 students has a mean score of 82. What is the mean score of all 50 students?
Total of scores: .
Mean: .
Check with the balance: 78 is 6 above 72 and 4 below 82, and , the inverse of the class sizes .
Answer
The mean is 78. The simple average of the class means, 77, ignores that the larger class has the higher mean.
Example 3: Consecutive even integers
The sum of nine consecutive even integers is 234. What is the largest of them?
The set is evenly spaced, so its mean equals its median: , the fifth (middle) number.
The largest is four steps of 2 above the middle: .
Check: the integers run from 18 to 34, and .
Answer
The largest is 34. Stepping up by 1 instead of 2 gives 30, the slip of treating even integers as consecutive integers.
Common traps
Averaging averages
The mean of two groups is the simple average of their means only when the groups are the same size. Otherwise go back to sums, or use the balance, and the larger group pulls the result its way.
A median from an unsorted list
The median is the middle of the sorted list. Questions often list values out of order, or add new values, so the old middle is no longer the middle. Sort first, every time.
Shifting a set and expecting the spread to change
Adding the same number to every value moves the mean but leaves the standard deviation unchanged. Multiplying every value by a number scales the standard deviation by the same factor (ignoring sign).
Ignoring "different" or "positive"
When you minimise the other values to make one value as large as possible, the conditions decide how small they may be. Different positive integers can be no smaller than 1, 2, 3 and so on; values above the median must exceed it if the numbers are different.
Check yourself
Answer each question before you open its answer.
Question 1: A sixth number lifts the mean
Problem Solving
The mean of five numbers is 18. When a sixth number is added, the mean of the six numbers is 20. What is the sixth number?
- A.20
- B.22
- C.30
- D.32
- E.120
Show the answer
Answer: C. 30
Working
Sum of five: . Sum of six: . The sixth number is . Check: it equals the new mean plus 2 for each of the five old numbers, .
Why the other options are wrong
- A. 20 is the new mean, not the added number; adding 20 would lift the mean only to .
- B. This adds the rise of 2 only once; the new number must supply 2 extra for each of the five original numbers.
- D. This adds 2 for six numbers; only the five original numbers needed lifting.
- E. 120 is the sum of all six numbers, not the sixth number.
What carries over
Turn every mean into a sum before adding or removing values.
Question 2: Largest value under a mean and median
Problem Solving
A list of five different positive integers has a mean of 12 and a median of 14. What is the greatest possible value of the largest integer in the list?
- A.28
- B.29
- C.30
- D.43
- E.46
Show the answer
Answer: A. 28
Working
The five integers add to . In order, . To make as large as possible, make the others as small as allowed: , , . Then . Check: has sum 60, mean 12 and median 14.
Why the other options are wrong
- B. This sets the fourth number equal to the median, 14, but the integers must be different, so it has to be at least 15.
- C. This repeats values (), ignoring that the integers are different.
- D. This leaves out the fourth number, which must be larger than 14 and also counts towards the sum.
- E. This subtracts only the median from the sum of 60, as if the other three numbers could be zero.
What carries over
To maximise one value, minimise all the others within every stated condition.
Question 3: Which set is less spread out?
Problem Solving
Set is . Which of the following sets has a smaller standard deviation than ?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: D.
Working
has mean 18, and its squared distances from the mean are , a total of 160, so its variance is . Adding another 18, the mean itself, keeps the mean at 18 and the total at 160 but spreads it over six values: . The standard deviation therefore falls. Each other option keeps or increases the spread.
Why the other options are wrong
- A. Adding 5 to every value moves the set without changing its spread; the standard deviation is the same.
- B. Doubling every value doubles every distance from the mean, so the standard deviation doubles.
- C. The two outer values moved further from the mean of 18, so the spread increased.
- E. 34 lies far from the mean, so adding it increases the spread.
What carries over
Adding a value at the mean lowers the standard deviation; shifting all values leaves it alone.
Key points
Sum = mean × number of values: switch to sums first.
A weighted mean lies closer to the larger group.
Sort before finding a median; in an evenly spaced set, mean = median = (first + last) ÷ 2.
Shifting values leaves the standard deviation alone; scaling scales it; a value at the mean lowers it.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.