Lesson 11 of 40 · Chemistry

Oxidation numbers and electron transfer

Assign oxidation numbers, identify oxidising and reducing agents, and balance electron transfer alongside atoms and charge.

About 19 minutes

In this lesson

  • Assign oxidation numbers using charge balance.
  • Identify oxidation, reduction and the corresponding agents.
  • Balance simple redox reactions by electron accounting.

The idea

Use oxidation numbers as bookkeeping

Oxidation numbers assign electrons according to a formal accounting convention. They help track electron transfer even when a reaction involves covalent compounds rather than isolated ions. A monatomic ion has an oxidation number equal to its charge. An element in its uncombined form has oxidation number zero, whether it is written as individual metal atoms or as a molecule such as oxygen gas. The sum of oxidation numbers, each multiplied by the relevant atom count, equals the species' overall charge.

Common rules simplify the calculation. Hydrogen is usually +1 when bonded to non-metals; oxygen is usually −2 in ordinary compounds. Group 1 metals are normally +1 and group 2 metals +2 in their compounds. These rules have exceptions: oxygen in a peroxide is −1, and hydrogen in a metal hydride is −1. A question about an ordinary oxide and a question about a peroxide therefore need different starting assumptions. State which rule is applicable before solving for an unknown value.

For an unknown oxidation number, write a short equation. In a neutral molecule, the total must be zero; in a polyatomic ion, it must equal the ion's charge. Multiply oxygen's value by the number of oxygen atoms and include all other contributions. Solving the resulting linear equation prevents mistakes with negative ionic charge. Do not confuse a central atom's oxidation number with the charge of the whole ion: the ion's charge is the sum over every atom.

Identify both changes before naming the agents

Oxidation is loss of electrons and corresponds to an increase in oxidation number. Reduction is gain of electrons and corresponds to a decrease. The two changes occur together. A species that is oxidised provides electrons and acts as the reducing agent. A species that is reduced accepts electrons and acts as the oxidising agent. The agent name describes its effect on the other participant, which is why the naming can initially feel reversed.

Consider a metal atom that becomes a doubly positive ion. It has lost two electrons and is oxidised. If another ion gains those electrons and becomes a neutral metal, it is reduced. The original metal atom is the reducing agent, while the ion accepting electrons is the oxidising agent. Identify the actual reactant species carrying the changing atom. A spectator ion that appears unchanged on both sides does not become an oxidising agent simply because it has a negative charge.

Balance electrons as well as material

A half-equation isolates one electron change. For example, a neutral atom forming a +2 ion releases two electrons. A +3 ion becoming a +2 ion consumes one electron. To combine such changes, multiply the second half-equation by two so that the electron counts match. Add the half-equations and cancel electrons appearing on opposite sides. The final equation must conserve every element and total electrical charge. A balanced atom count alone is not enough for an ionic equation.

For aqueous reactions, water, hydrogen ions or hydroxide ions may participate depending on the specified conditions. These species are accounting tools with chemical meaning, not arbitrary corrections. In an acidic medium, hydrogen ions can balance hydrogen after water balances oxygen. In a basic medium, hydroxide and water are used consistently. Do not import hydrogen ions into a final basic-medium equation merely because an earlier intermediate calculation used them. For introductory problems, a supplied pair of simple half-equations often avoids this extra complication.

Connect electron transfer with reacting amounts

Once the equation is balanced, its coefficients give mole ratios just as in other stoichiometry. If one atom loses two electrons while each accepting ion gains one, two accepting ions are required per donor atom. Convert masses to moles before applying this ratio. Multiplying a half-equation changes its coefficient and total electrons, but not the oxidation number assigned to each atom. Check the finished result through two independent balances: the same number of atoms on each side and the same total charge on each side. This catches an omitted coefficient that either check alone might miss.

Worked examples

Example 1: An oxidation number in an ion

Find sulphur's oxidation number in SO42−\mathrm{SO_4^{2-}}, using oxygen −2.

  1. Four oxygen atoms contribute 4(−2)=−84(-2)=-8. The complete ion has charge −2.

  2. Write x−8=−2x-8=-2, so x=+6x=+6.

Answer

Sulphur is +6; −2 is the charge of the entire ion, not of sulphur alone.

Example 2: Combining electron changes

Zinc forms Zn2+ and Fe3+ becomes Fe2+. Balance the net electron-transfer equation.

  1. Zinc releases two electrons: Zn → Zn2+ + 2e−.

  2. Each Fe3+ takes one electron. Double that half-equation and cancel both electrons.

  3. Check that total charge is +6 on each side.

Answer

Zn+2Fe3+→Zn2++2Fe2+\mathrm{Zn}+2\mathrm{Fe^{3+}}\rightarrow\mathrm{Zn^{2+}}+2\mathrm{Fe^{2+}}.

Common traps

  • Calling the oxidised species the oxidising agent

    The oxidised species donates electrons, reducing its partner. It is the reducing agent; name the agent from its effect on the other species.

  • Balancing atoms while ignoring charge

    An ionic equation must conserve total charge. Sum the charges after multiplying each by its coefficient.

Check yourself

Answer each question before you open its answer.

Question 1: Oxidation numbers

Oxidation numbers

What is nitrogen's oxidation number in NO3−\mathrm{NO_3^-} when oxygen is −2?

  1. A.−1
  2. B.+3
  3. C.+5
  4. D.+6
  5. E.−5
Show the answer

Answer: C. +5

Working

Let the nitrogen value be x. Then x − 6 = −1, so x = +5.

Why the other options are wrong

  • A. This repeats the total ion charge without accounting for oxygen.
  • B. Three oxygen atoms contribute −6, so +3 does not give total −1.
  • D. This would make the complete ion neutral rather than −1.
  • E. A negative nitrogen value would make the total charge even more negative.

What carries over

Set the oxidation-number sum equal to the full species charge.

Question 2: Redox agents

Redox agents

A reactant accepts electrons and is reduced. What role does it play?

  1. A.Reducing agent
  2. B.Oxidising agent
  3. C.An unchanged spectator by definition
  4. D.A catalyst solely because it gains electrons
  5. E.A proton donor by definition
Show the answer

Answer: B. Oxidising agent

Working

By accepting electrons, the reactant allows its partner to be oxidised. It therefore acts as the oxidising agent.

Why the other options are wrong

  • A. A reducing agent donates electrons and is itself oxidised.
  • C. Electron acceptance changes the species and excludes the spectator role.
  • D. Electron gain alone does not establish regeneration as a catalyst.
  • E. Electron acceptance is not the same as proton donation.

What carries over

Agent names describe what the species causes in its partner.

Question 3: Redox stoichiometry

Redox stoichiometry

One metal atom releases three electrons. Each accepting ion takes one electron. How many accepting ions are needed per metal atom?

  1. A.1/3
  2. B.1
  3. C.2
  4. D.3
  5. E.6
Show the answer

Answer: D. 3

Working

Three one-electron gains balance one three-electron loss. The electron total cancels only with three accepting ions per donor atom.

Why the other options are wrong

  • A. This reverses the required acceptor-to-donor ratio.
  • B. One acceptor would consume only one of the three electrons.
  • C. Two acceptors would consume only two electrons.
  • E. Six acceptors would require twice the available electrons.

What carries over

Match the total electron gain to the total electron loss.

Key points

  • Oxidation-number sums equal the overall species charge.

  • Oxidation raises oxidation number; reduction lowers it.

  • The reducing agent is oxidised and the oxidising agent is reduced.

  • A redox equation conserves atoms, charge and electron transfer.

All questions here are original and written for UniExamer; none comes from the test maker.

Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.

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