Lesson 27 of 40 · Mathematics

The unit circle and trigonometric equations

Read signs and exact values from the unit circle, use double-angle identities and find every angle in a specified interval.

About 20 minutes

In this lesson

  • Read sine and cosine as coordinates on the unit circle.
  • Evaluate related angles and double angles.
  • List complete solutions within a stated interval.

The idea

Turn an angle into a point

Draw a circle of radius one centred at the origin. Start at the point one unit to the right of the centre and travel anticlockwise through an angle. The coordinates where you stop are the cosine (coseno) and sine (seno) of that angle, in that order. The tangent (tangente) is the vertical coordinate divided by the horizontal one whenever the horizontal coordinate differs from zero. The signs now come from ordinary coordinates. In the upper left quarter, for example, the sine is positive, the cosine negative and the tangent negative.

Radians (radianti) measure a turn by the arc length it cuts off divided by the radius. Around a unit circle the full distance is 2π2\pi, so half a turn is π\pi radians or 180 degrees. To convert degrees to radians multiply by π/180\pi/180. A negative angle travels clockwise. Adding a whole turn leaves both final coordinates unchanged, although it changes the number describing the journey. Opposite points have both coordinate signs reversed and hence the same tangent where the ratio exists.

Use one small triangle more than once

Cut an equilateral triangle of side two down its middle. Each half has hypotenuse two and short leg one. Pythagoras gives the long leg as 3\sqrt3. Dividing every side by two makes a unit hypotenuse. For the angle of thirty degrees the vertical leg is the short one, so its sine is one half. Exchanging the roles of the legs gives the complementary angle of sixty degrees. A right triangle with two equal legs instead gives both coordinates as 2/2\sqrt2/2 at forty-five degrees.

For an angle outside the first quadrant, find the acute angle its terminal ray makes with the horizontal axis. Reflect the corresponding first-quadrant point into the correct quadrant. Reflection in the vertical axis reverses the first coordinate alone. Reflection in the horizontal axis reverses the second coordinate alone. You can therefore read the answer exactly even when the angle is expressed as a large multiple of a familiar fraction of a turn. Removing whole turns before reflecting saves work and leaves all coordinates unchanged.

Use the circle equation and double-angle rules

The circle equation gives cos⁡2t+sin⁡2t=1\cos^2 t+\sin^2 t=1. Given one coordinate you can recover the magnitude of the other by subtracting its square from one and taking a square root. Choose the sign from the quadrant. Without a location or another condition the sign may remain undetermined. If only a squared value is needed, keep it squared and avoid choosing a sign prematurely.

Doubling an angle moves the point around the circumference. It does not simply double a coordinate. The identities sin⁡(2t)=2sin⁡tcos⁡t\sin(2t)=2\sin t\cos t and cos⁡(2t)=cos⁡2t−sin⁡2t\cos(2t)=\cos^2 t-\sin^2 t describe the new position. The sine formula can be negative even if the original sine is positive. An angle starting in the second quadrant doubles into the lower half of the circle, which agrees with the negative product there.

Sweep through the requested interval

To solve a sine equation in one turn, draw a horizontal line at the requested height. Count the points at which it meets the circle and follow the turn from its specified start to identify the angles. A cosine equation uses a vertical line instead. If a line passes through a top, bottom or side extreme there may be just one distinct point, and outside the circle there are none. A tangent equation repeats after half a turn wherever the ratio is defined.

For an inequality, first mark the equality points and then follow the arcs where the coordinate satisfies the comparison. A strict inequality leaves the equality points out. For an interval covering multiple turns, add whole periods to the solutions and filter them against both endpoints. The coordinates at zero and a full turn coincide, but both angle values belong in the answer if the given closed interval includes both values and they satisfy the condition.

Worked examples

Example 1: A reflected point

Find the sine and cosine of 5π/65\pi/6.

  1. The angle is π−π/6\pi-\pi/6 and lies in the upper left quadrant.

  2. The reference point at π/6\pi/6 has coordinates (3/2,1/2)(\sqrt3/2,1/2). Reflect across the vertical axis.

Answer

The sine is 1/21/2 and the cosine is −3/2-\sqrt3/2.

Example 2: An inequality through one turn

Solve sin⁡t>3/2\sin t>\sqrt3/2 for 0≤t<2π0\le t<2\pi.

  1. The horizontal line at height 3/2\sqrt3/2 meets the circle at π/3\pi/3 and 2π/32\pi/3.

  2. The arc between them contains the top point of height 1. Everywhere else lies at or below the line.

Answer

The solution is π/3<t<2π/3\pi/3<t<2\pi/3.

Common traps

  • Losing a second angle

    A horizontal line between the extreme heights usually meets the circle twice. Read both points before adding any periods.

  • Taking the positive square root automatically

    A square identifies magnitude. Use the quadrant to decide the sign of the missing coordinate.

Check yourself

Answer each question before you open its answer.

Question 1: Signs after reflection

Trigonometry

What is cos⁡(7π/6)\cos(7\pi/6)?

  1. A.3/2\sqrt3/2
  2. B.−1/2-1/2
  3. C.−3/2-\sqrt3/2
  4. D.1/21/2
  5. E.−3-\sqrt3
Show the answer

Answer: C. −3/2-\sqrt3/2

Working

The angle is π+π/6\pi+\pi/6. Its point is opposite the point at π/6\pi/6, so the horizontal coordinate changes from 3/2\sqrt3/2 to −3/2-\sqrt3/2.

Why the other options are wrong

  • A. This reads the reference cosine without its quadrant sign.
  • B. This is the sine of the stated angle.
  • D. This is the positive sine of the reference angle.
  • E. This doubles the cosine magnitude beyond the unit circle.

What carries over

A half-turn reverses both coordinates.

Question 2: Doubling a turn

Trigonometry

If tt lies in the second quadrant and sin⁡t=3/5\sin t=3/5, what is sin⁡(2t)\sin(2t)?

  1. A.24/2524/25
  2. B.6/56/5
  3. C.7/257/25
  4. D.−12/25-12/25
  5. E.−24/25-24/25
Show the answer

Answer: E. −24/25-24/25

Working

The cosine is −1−9/25=−4/5-\sqrt{1-9/25}=-4/5. The double-angle sine is 2(3/5)(−4/5)=−24/252(3/5)(-4/5)=-24/25.

Why the other options are wrong

  • A. This uses a positive cosine in the second quadrant.
  • B. This doubles the sine itself.
  • C. This computes the double-angle cosine.
  • D. This omits the factor two in the double-angle sine.

What carries over

Find the signed coordinates before applying a double-angle identity.

Question 3: Two matching angles

Trigonometry

Which list gives every solution of cos⁡t=1/2\cos t=1/2 in 0≤t<2π0\le t<2\pi?

  1. A.π/3\pi/3 only
  2. B.π/3,5π/3\pi/3,5\pi/3
  3. C.π/6,5π/6\pi/6,5\pi/6
  4. D.2π/3,4π/32\pi/3,4\pi/3
  5. E.π/3,4π/3\pi/3,4\pi/3
Show the answer

Answer: B. π/3,5π/3\pi/3,5\pi/3

Working

The vertical line at x=1/2x=1/2 cuts the circle at angles π/3\pi/3 and 2π−π/3=5π/32\pi-\pi/3=5\pi/3.

Why the other options are wrong

  • A. This misses the lower intersection.
  • C. These have sine one half.
  • D. These have cosine negative one half.
  • E. The second point is opposite the first and has the wrong cosine.

What carries over

Use a vertical slice for an equation in cosine.

Key points

  • Cosine is the horizontal coordinate and sine the vertical one.

  • Choose signs by locating the terminal point.

  • Check every solution against the stated endpoints.

All questions here are original and written for UniExamer; none comes from the test maker.

Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.

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