Lesson 9 of 42 · Algebra
Systems of equations with two unknowns
Solve two-unknown systems by substitution or elimination, tell when there is one, no or infinitely many solutions, and intersect a line with a parabola.
About 22 minutes
In this lesson
- Solve a linear system in two unknowns by substitution or by elimination, choosing the quicker method.
- Decide from the coefficients whether a linear system has one solution, none or infinitely many.
- Solve a system of a line and a parabola, and find what a question asks for without solving fully when a combination is enough.
The idea
What a solution is
A solution of a system is a pair that satisfies every equation at once. Each linear equation is a straight line in the plane, so solving two of them means finding where the two lines meet.
Substitution
Isolate one unknown in the equation where it is easiest (a coefficient of or ), and substitute into the other:
So , and . Substitution is the natural choice when one equation is not linear, for example a parabola and a line.
Elimination
Multiply the equations by numbers that make the coefficients of one unknown equal or opposite, then add or subtract the equations to remove it. For
adding removes at once: . Elimination is usually faster when both equations are linear and no coefficient is .
Combinations: answer the question asked
A question may ask for an expression such as or , not for and . Before solving, see whether adding or subtracting the equations produces that expression directly. In the system above, the sum of the two equations is ; in the first system, adding to gives immediately.
One, none or infinitely many
Two lines in the plane meet once, never (parallel) or everywhere (the same line). For
the test is the number :
| Condition | Lines | Solutions |
|---|---|---|
| cross | exactly one | |
| , equations inconsistent | parallel, distinct | none |
| , one equation a multiple of the other | the same line | infinitely many |
When , the left sides are proportional. Compare the right sides with the same factor: if they match, the equations say the same thing; if not, they contradict each other. For example, and are the same line, while and are parallel.
A line and a parabola
To intersect with , substitute the line into the parabola. You get a quadratic in , and its discriminant tells you how the line sits:
- : two intersection points (a secant);
- : one point, the line is tangent;
- : no common point.
Each root gives a point; find its from the line, which is quicker, and check it in the parabola.
Word problems
Name the two unknowns explicitly, with units (" = number of adult tickets"), write one equation per independent fact, solve, then check the answer against the story: counts must be whole numbers, lengths positive. The check catches most setting-up errors.
Worked examples
Example 1: Elimination in one step
Solve and .
The coefficients are opposite, so add the equations: , .
Substitute into the first: , so .
Check in the second: .
Answer
. Subtracting the equations instead of adding them gives , which still has both unknowns and solves nothing.
Example 2: Counting solutions with a parameter
For which values of does the system , have exactly one solution? What happens for the other values?
Compute .
Exactly one solution when , that is .
At : the first equation is ; dividing the second by 3 gives . The same left side cannot equal both 4 and , so there is no solution.
Answer
One solution for every ; no solution at , where the lines are parallel and distinct. Concluding "infinitely many" at skips the comparison of the right sides.
Example 3: Where a line meets a parabola
Find the intersection points of and .
Set the two expressions for equal: , so .
Factor: , so or .
Find from the line: gives ; gives .
Check in the parabola: and .
Answer
The points are and . Stopping at and gives only half of each answer; a point needs both coordinates.
Example 4: A word problem
A theatre sold 40 tickets for €395. Adult tickets cost €12 and child tickets €7. How many of each were sold?
Let be the number of adult tickets and the number of child tickets: and .
Substitute : , so and .
Then . Check the money: .
Answer
23 adult and 17 child tickets. If a setup gives a fraction of a ticket, the equations are wrong, not the arithmetic.
Common traps
Substitution sign slips
From the substitution is , not . After solving, put the pair back into both original equations; one check is not enough.
Assuming a proportional system has no solution
When the left sides are proportional, compare the right sides with the same factor. Matching right sides mean the same line and infinitely many solutions; only mismatched ones mean none.
Answering with x when the question asks for something else
Read what is asked: , , the product , or the number of solutions. Often a combination of the equations gives it directly, and finding alone answers nothing.
Taking y from the wrong curve
For a line and a parabola both curves give the same at a true intersection point, so either works, but a slip in squaring a negative is common. Use the line for speed and the parabola as a check.
Check yourself
Answer each question before you open its answer.
Question 1: Asked for a combination
Algebra: systems
If and , what is the value of ?
- A.6
- B.7
- C.8
- D.9
Show the answer
Answer: C. 8
Working
Add the two equations: , so directly. Check by solving: gives , so , , and .
Why the other options are wrong
- A. This subtracts the equations, which gives : a different combination from the one asked.
- B. This swaps the solution, using ; that pair does not satisfy .
- D. This is , using 3 as the coefficient of as well as of .
What carries over
Look for a combination of the equations that gives the requested expression before solving for each unknown.
Question 2: A system with a parameter
Algebra: systems
Consider the system and . Which statement is true?
- A.At the system has no solution.
- B.At the system has infinitely many solutions.
- C.The system has exactly one solution for every value of .
- D.At the system has infinitely many solutions.
Show the answer
Answer: B. At the system has infinitely many solutions.
Working
, which is zero only at ; for every other there is exactly one solution. At the first equation is , and twice it is , the second equation exactly. The two equations describe the same line, so there are infinitely many solutions.
Why the other options are wrong
- A. At the second equation is exactly twice the first (), so the lines coincide; there are infinitely many solutions, not none.
- C. At the expression is zero, so the solution is not unique there.
- D. This comes from a cross-multiplication slip, setting . The left sides are proportional when , which gives .
What carries over
When the left sides are proportional, compare the right sides to decide between none and infinitely many.
Question 3: Line meets parabola
Algebra: systems
The line meets the parabola at two points. What is the sum of the -coordinates of these points?
- A.
- B.
- C.
- D.
Show the answer
Answer: D.
Working
Set : , so and or . The points are and ; check with the line: and . The sum of the -coordinates is .
Why the other options are wrong
- A. This is the product of the -coordinates, , not a sum of -coordinates.
- B. This is the sum of the -coordinates, .
- C. This takes at , forgetting that ; the line agrees: .
What carries over
Substitute to get a quadratic in x, then find each y and check it on both curves.
Key points
Use substitution when one equation is easy to rearrange or not linear; elimination when both are linear.
means exactly one solution; if it is zero, compare the right sides: same line or parallel lines.
A line and a parabola meet in two, one or no points, according to the discriminant of the resulting quadratic.
Read what is asked: a combination of the equations often gives it without solving.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.