Lesson 16 of 42 · Geometry and trigonometry

Plane geometry formulas: triangles, circles and quadrilaterals

Know the area and perimeter formulas for triangles, circles, squares, trapezoids and rhombi, and find the missing length each one needs.

About 20 minutes

In this lesson

  • Recall and apply the area and perimeter formulas for the triangle, circle, square, rectangle, trapezoid and rhombus.
  • Find a missing height, side or diagonal with the Pythagorean theorem before using a formula.
  • Split or subtract figures to find the area of a composite region, and predict how area changes when lengths are scaled.

The idea

Why formulas are rarely enough on their own

Plane geometry questions almost never hand you every number a formula needs. A trapezoid comes with its slanted side instead of its height; a rhombus comes with a side and one diagonal; a square is described only through the circle around it. The formula is the last step. The real work is finding the one missing length, and that length nearly always comes from a right triangle hidden in the figure.

The formulas to know cold

Figure Area Perimeter or circumference
Triangle, base bb, height hh 12bh\frac{1}{2}bh sum of the three sides
Equilateral triangle, side ss 34s2\frac{\sqrt{3}}{4}s^2 3s3s
Rectangle, sides aa, bb abab 2(a+b)2(a+b)
Square, side ss, diagonal dd s2=d22s^2 = \frac{d^2}{2} 4s4s
Rhombus, diagonals d1d_1, d2d_2, side ss d1d22\frac{d_1 d_2}{2} 4s4s
Trapezoid, parallel sides aa, bb, height hh (a+b)h2\frac{(a+b)h}{2} sum of the four sides
Circle, radius rr πr2\pi r^2 2πr2\pi r

The height of a triangle or trapezoid is always measured at a right angle to the base, never along a slanted side. Any side of a triangle can serve as the base, as long as the height is the one drawn to that side. In a right triangle the two legs are a base and its height, so its area is half the product of the legs.

The right triangle behind every missing length

The Pythagorean theorem says that in a right triangle with legs aa, bb and hypotenuse cc, a2+b2=c2a^2 + b^2 = c^2. Without a calculator it helps to recognise the common whole-number triples: 3,4,53, 4, 5; 5,12,135, 12, 13; 8,15,178, 15, 17; 7,24,257, 24, 25; and their multiples such as 6,8,106, 8, 10.

Three hidden right triangles come up again and again:

  • Equilateral triangle. The height splits it into two right triangles with hypotenuse ss and short leg s2\frac{s}{2}, so the height is 32s\frac{\sqrt{3}}{2}s. Half the base times that height gives the area formula in the table.
  • Rhombus. Its diagonals cross at right angles and cut each other in half. Each of the four small right triangles has legs d12\frac{d_1}{2} and d22\frac{d_2}{2} and hypotenuse equal to the side ss. So any two of side, first diagonal and second diagonal give the third.
  • Isosceles trapezoid. Drop a perpendicular from each end of the shorter parallel side. The two right triangles at the ends each have a horizontal leg of b−a2\frac{b - a}{2}, where bb is the longer parallel side, and the slanted side as hypotenuse. The vertical leg is the height.

A square is both a rectangle and a rhombus: its diagonals are equal, so d⋅d2=d22\frac{d \cdot d}{2} = \frac{d^2}{2} gives its area from the diagonal, and its diagonal is s2s\sqrt{2}.

Circles, arcs and sectors

Turn whatever is given into the radius first. A circumference of 18π18\pi means r=9r = 9 and an area of 81π81\pi. A sector with central angle θ\theta degrees is the fraction θ360\frac{\theta}{360} of the whole circle, so its area is θ360πr2\frac{\theta}{360}\pi r^2 and its arc is θ360⋅2πr\frac{\theta}{360} \cdot 2\pi r. A quarter circle of radius 4 has area 4π4\pi and arc 2π2\pi.

When a square sits inside a circle with its four corners on the circle, the square's diagonal is a diameter. When a circle sits inside a square touching all four sides, the circle's diameter equals the square's side. Read which one the question describes; the two give very different numbers.

Composite regions: add or subtract

A shaded region is usually a big figure minus a small one, or two simple figures joined along a side. Name the pieces before calculating. "The region inside the circle but outside the square" is circle area minus square area. An L-shaped floor plan is two rectangles. Leave π\pi and roots in exact form until the end: the answer options usually do too.

Scaling

If every length of a figure is multiplied by kk, its perimeter is multiplied by kk and its area by k2k^2. Doubling the sides of a square multiplies its area by 4; a circle whose radius grows by 10% has an area 1.12=1.211.1^2 = 1.21 times as large, 21% more. This is often the fastest route to an answer, and it is a good check on any area you compute.

Worked examples

Example 1: A rhombus from its diagonals

A rhombus has diagonals of length 10 and 24. Find its area, its side, its perimeter and the distance between two opposite sides.

  1. Area from the diagonals: 10⋅242=120\frac{10 \cdot 24}{2} = 120.

  2. The diagonals bisect each other at right angles, so each of the four small right triangles has legs 55 and 1212. The side is the hypotenuse: 25+144=169=13\sqrt{25 + 144} = \sqrt{169} = 13.

  3. Perimeter: 4⋅13=524 \cdot 13 = 52.

  4. A rhombus is a parallelogram, so its area is also side times the height between opposite sides: 13h=12013h = 120, which gives h=12013h = \frac{120}{13}.

  5. Check: the four small triangles each have area 5⋅122=30\frac{5 \cdot 12}{2} = 30, and 4⋅30=1204 \cdot 30 = 120, as before.

Answer

Area 120120, side 1313, perimeter 5252, distance between opposite sides 12013\frac{120}{13}. Multiplying the diagonals without halving gives 240240, a common slip.

Example 2: A trapezoid given its slanted sides

An isosceles trapezoid has parallel sides 6 and 14 and each slanted side equal to 5. Find its area.

  1. Describe the figure: the longer side, 14, is the bottom; the shorter side, 6, is centred above it. Dropping a perpendicular from each end of the top side leaves a 6×h6 \times h rectangle in the middle and two equal right triangles at the ends.

  2. Each end triangle has a horizontal leg of 14−62=4\frac{14 - 6}{2} = 4 and hypotenuse 5 (the slanted side).

  3. The height is the vertical leg: 25−16=3\sqrt{25 - 16} = 3, a 3,4,53, 4, 5 triangle.

  4. Area: (6+14)⋅32=30\frac{(6 + 14) \cdot 3}{2} = 30. Check by pieces: rectangle 6⋅3=186 \cdot 3 = 18 plus two triangles of 4⋅32=6\frac{4 \cdot 3}{2} = 6 each gives 3030.

Answer

The area is 3030. Using the slanted side 5 as if it were the height gives 5050, which is too big: the height of a trapezoid is always shorter than its slanted sides.

Example 3: A square inside a circle

A square has its four vertices on a circle of radius 5. Find the area of the region inside the circle but outside the square.

  1. Corners on the circle means the square's diagonal passes through the centre and is a diameter: d=10d = 10.

  2. Square area from the diagonal: d22=1002=50\frac{d^2}{2} = \frac{100}{2} = 50. Check with the side: s=102=52s = \frac{10}{\sqrt{2}} = 5\sqrt{2}, and s2=50s^2 = 50.

  3. Circle area: π⋅52=25π\pi \cdot 5^2 = 25\pi.

  4. The region is the difference: 25π−5025\pi - 50. As a sense check, 25π25\pi is about 78.578.5, so the region is about 28.528.5, positive and smaller than the square, as the picture suggests.

Answer

The region has area 25π−5025\pi - 50. Taking the square's side to be the diameter gives a square of area 100100, larger than the circle itself, which is impossible for a square drawn inside it.

Common traps

  • Using a slanted side as the height

    In a trapezoid, parallelogram or non-right triangle the slanted side is longer than the height. Multiplying by it overstates the area. Whenever the height is not given, draw the perpendicular in your head and find it with the Pythagorean theorem.

  • Forgetting the half

    Triangle, rhombus and trapezoid formulas all contain a division by 2. Forgetting it doubles the answer, and the doubled value is a favourite wrong option. Check against a rough estimate: a rhombus must have less area than the rectangle built on its two diagonals.

  • Treating a rhombus as a square

    A rhombus has four equal sides, but its area is not s2s^2 unless its angles are right angles. With side 10, a rhombus can have any area up to 100. Use the diagonals, or side times height.

  • Radius, diameter and inscribed or circumscribed

    A square inside a circle has the diameter as its diagonal; a square around a circle has the diameter as its side. Mixing them changes the square's area by a factor of 2. Say which figure is inside before you write a number.

Check yourself

Answer each question before you open its answer.

Question 1: Rhombus from a side and a diagonal

Plane geometry

A rhombus has side 10 and one diagonal of length 12. What is its area?

  1. A.4848
  2. B.9696
  3. C.100100
  4. D.192192
Show the answer

Answer: B. 9696

Working

The diagonals bisect each other at right angles, so half of the known diagonal (6) and half of the unknown one form a right triangle with the side 10 as hypotenuse. The unknown half is 100−36=8\sqrt{100 - 36} = 8, so the second diagonal is 16. Area: 12⋅162=96\frac{12 \cdot 16}{2} = 96.

Why the other options are wrong

  • A. This is the product of the half-diagonals, 6⋅86 \cdot 8. The area is the product of the full diagonals divided by 2, which is twice this.
  • C. This treats the rhombus as a square of side 10. A rhombus has that area only when its angles are right angles, and then its diagonals would both be 10210\sqrt{2}, not 12.
  • D. This multiplies the diagonals, 12⋅1612 \cdot 16, and forgets to divide by 2.

What carries over

In a rhombus, the side and the two half-diagonals form a right triangle; find the missing diagonal before using the area formula.

Question 2: A square inside a circle

Plane geometry

A circle has circumference 12π12\pi. A square is drawn with all four vertices on the circle. What is the area of the square?

  1. A.3636
  2. B.7272
  3. C.36π36\pi
  4. D.144144
Show the answer

Answer: B. 7272

Working

From 2πr=12π2\pi r = 12\pi, the radius is 6 and the diameter 12. The square's diagonal is a diameter, so its area is 1222=72\frac{12^2}{2} = 72. Check: the side is 122=62\frac{12}{\sqrt{2}} = 6\sqrt{2}, and (62)2=72(6\sqrt{2})^2 = 72.

Why the other options are wrong

  • A. This makes the side of the square equal to the radius, 6. The radius reaches from the centre to a vertex, which is half the diagonal, not the side.
  • C. This is the area of the circle, not of the square inside it.
  • D. This makes the side equal to the diameter, 12. That is the square drawn around the circle, whose sides touch it; here the vertices are on the circle.

What carries over

A square with its vertices on a circle has a diameter as its diagonal, and its area is half the diagonal squared.

Question 3: A right trapezoid

Plane geometry

A trapezoid has two right angles. Its parallel sides measure 7 and 13, and its slanted side measures 10. What is its area?

  1. A.8080
  2. B.100100
  3. C.104104
  4. D.160160
Show the answer

Answer: A. 8080

Working

The two right angles sit on the side perpendicular to the parallel sides, so that side is the height. Dropping a perpendicular from the end of the shorter side leaves a right triangle with horizontal leg 13−7=613 - 7 = 6 and hypotenuse 10, so the height is 100−36=8\sqrt{100 - 36} = 8. Area: (7+13)⋅82=80\frac{(7 + 13) \cdot 8}{2} = 80.

Why the other options are wrong

  • B. This uses the slanted side 10 as the height. The height is the side perpendicular to the parallel sides, which is shorter than 10.
  • C. This is the longer parallel side times the height, 13⋅813 \cdot 8, as if the figure were a rectangle; it ignores the triangular corner that is missing.
  • D. This is (7+13)⋅8(7 + 13) \cdot 8: the sum of the parallel sides times the height, without dividing by 2.

What carries over

When a trapezoid gives a slanted side instead of a height, find the height from the right triangle that the slanted side closes.

Key points

  • Triangle 12bh\frac{1}{2}bh, rhombus d1d22\frac{d_1 d_2}{2}, trapezoid (a+b)h2\frac{(a+b)h}{2}, circle πr2\pi r^2: three of the four divide by 2.

  • The missing height, side or diagonal almost always comes from a right triangle hidden in the figure.

  • A square with its vertices on a circle has a diameter as its diagonal; a square around a circle has a diameter as its side.

  • Scaling every length by kk scales the area by k2k^2.

All questions here are original and written for UniExamer; none comes from the test maker.

Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.

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