Lesson 39 of 42 · Quick revision
Revision: geometry, counting, probability and statistics
Lines, circles, parabolas, areas and volumes, the counting matrix, probability rules, averages and compound percentages on one sheet, with drills.
About 30 minutes
In this lesson
- Recall the line, circle and parabola formulas and read centres, radii and vertices from equations.
- Choose between permutations, arrangements with repeats and combinations by asking whether order matters.
- Use inclusion–exclusion and the complement rule for "or" and "at least one" probabilities.
- Work averages through totals and chain percentage changes as multipliers.
The idea
How to use this sheet
These formulas come up across the mathematics questions, and without a calculator the fastest route is usually the formula plus a quick sanity check. Read each block, cover it, and say it back; then do the drills below without looking.
Lines in the plane
For points and :
| Quantity | Formula |
|---|---|
| Distance | |
| Midpoint | |
| Slope | (for ) |
| Line through a point with slope | |
| Parallel lines | |
| Perpendicular lines (neither vertical) | |
| Distance from to |
The line through and has slope , so , that is ; both points satisfy it. The distance from to is . A line written as has slope when .
Circles
A circle with centre and radius is . In the expanded form :
It is a real circle only if , and only if and have equal coefficients and there is no term. Completing the square gives the same results when you forget the formulas.
Parabolas
For with , the vertex has ; substitute it to get . The axis of symmetry is the vertical line . The parabola opens upwards if (the vertex is a minimum) and downwards if . For : and , so the vertex is , a minimum.
Areas and volumes
| Figure | Formula |
|---|---|
| Triangle | |
| Equilateral triangle, side | |
| Trapezoid | |
| Rhombus, diagonals , | |
| Circle | area , circumference |
| Sector with angle degrees | arc , area |
| Cylinder | |
| Cone | |
| Sphere |
A sector's arc and area are the same fraction of the full circumference and the full area, because both are set by the angle.
The counting matrix
Ask one question first: does the order of the chosen items matter?
| Model | Order matters? | Formula | Example |
|---|---|---|---|
| Arranging all items | yes | 5 books on a shelf: | |
| Ordered choice of from | yes (ranked slots) | a representative and a deputy from 6: | |
| Arranging items with repeats | yes, but identical items are interchangeable | the letters of BOCCONI: | |
| Unordered choice of from | no (a group) | 4 delegates from 12: |
Independent stages multiply (the product rule); separate cases that cannot happen together add (the sum rule).
Probability
With equally likely outcomes, . Two rules do most of the work:
- Inclusion–exclusion: . The overlap is counted inside both and , so subtract it once.
- Complement: . For four tosses of a fair coin, , so .
For independent events, .
Statistics
- Work through totals: total mean count. Class A (20 students, mean 80) and class B (30 students, mean 70) together have mean , not the plain average 75 of the two means.
- Median: the middle value of the sorted data (the mean of the two middle values when the count is even). It is resistant to outliers: in a set of three or more values, making the largest value much larger moves the mean but leaves the median where it is.
- Shifting and scaling: adding to every value adds to the mean and median and leaves the range, variance and standard deviation unchanged. Multiplying every value by multiplies the mean by , the standard deviation by and the variance by .
Compound percentages
A rise of is the multiplier , a fall is , and successive changes multiply. Up 20% then down 20% is : a net fall of 4%, not 0%. To undo a change, divide by its multiplier: after a 15% discount a laptop costs €680, so the original price was euros (dividing top and bottom by 17 gives ). Adding 15% to 680 gives 782, which is wrong.
Worked examples
Example 1: Centre and radius from the expanded form
Find the centre and radius of the circle .
Read , , . The centre is .
The radius: , so .
Check by completing the square: , so .
Answer
Centre , radius 5. The usual slips are the signs of the centre, , and subtracting 12 instead of adding it, which gives .
Example 2: From a sector to the whole circle
A sector has an arc of length , and its area is of the area of the full circle. Find the area of the full circle.
The sector's area and arc are the same fraction of the whole, because both are fixed by the angle. So the arc is of the circumference: , and .
From , the radius is .
The full area is .
Second route: a sector's area is , and .
Answer
. Stopping at the sector's own area, , answers a different question.
Example 3: Arrangements with repeated letters
How many different arrangements are there of the letters of BOCCONI?
Count the letters: B, O, C, C, O, N, I, so 7 letters with O twice and C twice; the other three appear once.
If all 7 were different there would be arrangements. Swapping the two Os, or the two Cs, gives the same word, so divide by for each: .
Second route: choose 2 of the 7 positions for the Cs (), 2 of the remaining 5 for the Os (), and arrange B, N, I in the last 3 (): .
Answer
- Using counts each word four times; dividing by only once gives 2520.
Example 4: Inclusion–exclusion with a 40-card deck
A deck has 40 cards: four suits (coins, cups, swords and clubs) of 10 cards each, and each suit has one ace. One card is drawn at random. What is the probability that it is a coin or an ace?
and .
The ace of coins is in both groups: .
Inclusion–exclusion: .
Second route, by counting: the 10 coins plus the 3 aces of the other suits make 13 favourable cards out of 40.
Answer
. Adding without subtracting the overlap gives , which counts the ace of coins twice.
Common traps
Perpendicular slope: only half the change
A perpendicular slope is the negative reciprocal: slope becomes . Changing only the sign () or only flipping the fraction () gives lines that are not perpendicular. Check by multiplying: the product must be .
Circle signs and the radius squared
has centre , because , and radius 4, not 16. In the expanded form, : a negative makes larger.
Ordered or unordered?
"Choose a president and a secretary" is ordered (the roles differ); "choose a committee of two" is not. Using for distinct roles undercounts by , and using for a group overcounts by . Ask whether swapping two chosen people gives a different outcome.
Counting the overlap twice
"Or" in probability includes both. Adding and without subtracting is right only when the events cannot happen together. If the sum comes out above 1, you have certainly double-counted.
Averaging averages
The mean of two groups is the plain average of their means only when the groups are the same size. Otherwise convert each mean into a total, add the totals, and divide by the total count.
Check yourself
Answer each question before you open its answer.
Question 1: A perpendicular line through a point
Mathematics: analytical geometry
Which line passes through and is perpendicular to ?
- A.
- B.
- C.
- D.
Show the answer
Answer: A.
Working
Rewrite the given line as , so its slope is . A perpendicular slope is . Through : , so . Check: at , . All four lines pass through the point, so the slope alone decides.
Why the other options are wrong
- B. This keeps the given slope , so it is the parallel line through the point.
- C. This only changes the sign of the slope; the product is not .
- D. This flips the fraction but keeps the sign; the product is , not .
What carries over
For a perpendicular line, flip the slope and change its sign, then check that the product of the slopes is −1.
Question 2: Roles and a committee
Mathematics: discrete mathematics
A club has 9 members. It elects a president and a treasurer (two different people), and then picks a 2-person events committee from the 7 members left. In how many ways can this be done?
- A.126
- B.756
- C.1512
- D.3024
Show the answer
Answer: C. 1512
Working
The two roles are ordered: ways. The committee is an unordered pair from the remaining 7: . The stages are independent, so multiply: .
Why the other options are wrong
- A. This is : it treats all four people as one unordered group and ignores that president and treasurer are different roles.
- B. This is : it treats the president and treasurer as an unordered pair, so it halves the count.
- D. This is : it treats the two committee places as ordered, so each committee is counted twice.
What carries over
Split a selection into stages, decide for each stage whether order matters, and multiply the stages.
Question 3: At least one six
Mathematics: probability
A fair die is rolled three times. What is the probability of getting at least one six?
- A.
- B.
- C.
- D.
Show the answer
Answer: B.
Working
Use the complement. The probability of no six in one roll is , so in three independent rolls it is . Then . Check by cases: exactly one six , exactly two , three ; total .
Why the other options are wrong
- A. This is the probability of exactly one six, ; it leaves out two and three sixes.
- C. This adds three times, which counts the outcomes with more than one six more than once.
- D. This is the probability of no six at all; it still has to be subtracted from 1.
What carries over
For "at least one", find the probability of none and subtract it from 1.
Key points
Perpendicular slopes multiply to −1; parallel slopes are equal.
In the centre is and ; the parabola's vertex is at .
Counting: order matters gives arrangements, order does not gives combinations, and repeated items divide by the factorial of each repeat.
Probability: subtract the overlap for "or", and use 1 minus "none" for "at least one".
Averages go through totals, and percentage changes chain as multipliers.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.