Lesson 37 of 46 · Geometry
Three-dimensional figures: volume, surface area and diagonals
Find volumes and surface areas of boxes, cubes, cylinders and prisms, scale them correctly, and count how many objects really fit inside.
About 20 minutes
In this lesson
- Find the volume and surface area of a rectangular solid, a cube, a cylinder and a right prism.
- Find the space diagonal of a box with the Pythagorean theorem.
- Scale surface areas and volumes when every length changes by the same factor.
- Count how many objects fit in a container dimension by dimension.
The idea
One idea behind most volumes
A solid whose cross-section stays the same from one end to the other (a box, a cube, a cylinder, any right prism) has
Picture stacking identical thin slices of the base, one on another, until the stack is as tall as the solid. That single idea gives every formula below, so you need to remember the base area, not a list.
| Solid | Volume | Surface area |
|---|---|---|
| Rectangular solid | ||
| Cube with edge | ||
| Cylinder, radius , height | ||
| Right prism | base area height | two bases plus the rectangular sides |
Surface area: list the faces
Surface area is the total area of everything you could paint on the outside. A box has three pairs of matching rectangles, which is where the comes from. A cylinder has two circular ends, , and a curved side. Unroll the side and it becomes a rectangle whose width is the circumference and whose height is , so its area is .
Read what a question wants painted or covered. An open-topped tank has only one circular end; a label round a can covers only the curved side (the lateral area). Listing the faces in words before you add saves you from including a face that is not there or missing one that is.
The space diagonal
The longest straight segment inside a box runs from one corner to the opposite corner, through the middle. Find it with two right triangles. The diagonal of the floor is . That floor diagonal and the vertical edge are the legs of a second right triangle standing upright inside the box, so
For a cube with edge this is . A box measuring has a space diagonal of .
Describing a solid in words
Without a picture, a solid is fixed by naming its shape and its measurements: "a cylinder standing on one circular end, with radius 3 and height 10", or "a box with a square base of side 4 and height 9". When a solid is cut, filled or stacked, say what changes and what stays fixed. Pouring water from one container into another keeps the volume of water; the new depth comes from dividing that volume by the new base area.
Scaling
If every length of a solid is multiplied by , its surface area is multiplied by and its volume by . Double a cube's edge and its surface area becomes 4 times as large while its volume becomes 8 times as large. Volume ratios grow much faster than length ratios: a cube with three times the edge holds 27 times as much.
Units and fitting
Cubic units convert by the cube of the length factor: 1 metre is 100 centimetres, so .
When rigid objects are packed into a container, do not divide volumes. Work one dimension at a time: how many fit along the length, along the width and up the height, each rounded down to a whole number, then multiply. Space left over in one direction cannot be combined with space left over in another, because a cube cannot be cut to fill the gaps. Dividing volumes gives only an upper bound that is often not reachable.
Beyond boxes and cylinders
Geometry is one of the four content areas of the Quantitative Reasoning measure. This lesson covers solids with a constant cross-section, where base times height applies. For any solid, the same habits work: name each face or base in words, find its area with the plane formulas, and keep track of which measurements are lengths, areas and volumes.
Worked examples
Example 1: Volume, surface area and diagonal of a box
A rectangular box measures by by . Find its volume, its total surface area and the length of its space diagonal.
Volume: .
Surface area: the three pairs of faces have areas , and , so the total is .
Space diagonal: the floor diagonal of the face is ; with the edge it forms a right triangle, so . The formula agrees: .
Answer
Volume , surface area , space diagonal . Adding the three face areas once, , gives the tempting wrong surface area: each face has a matching opposite face.
Example 2: Pouring water between cylinders
A cylindrical tank of radius and height holds water to a depth of . All of the water is poured into an empty cylinder of radius . How deep is the water in the second cylinder?
The volume of water stays the same. In the first tank it is .
In the second cylinder the base area is .
Depth .
Check by ratios: the base area falls from to , by a factor of , so the depth rises by the same factor: .
Answer
The water is deep. Scaling the depth by the ratio of the radii, , is the tempting wrong answer; base areas go with the square of the radius.
Example 3: How many cubes really fit
A box has inside dimensions by by . How many cubes with edge can be packed inside it, with their faces parallel to the box's faces?
Along the 10 side: cubes. Along the 7 side: , so cubes. Along the 5 side: , so cubes.
Multiply the whole numbers: cubes.
Compare with dividing volumes: . The extra space is a slab 1 unit thick along one side and another along the top, and no whole cube fits in either.
Answer
cubes fit. Dividing the volumes and rounding down to 43 is the tempting wrong answer.
Common traps
Scaling a volume by the length factor
Multiply every length by and the volume grows by , the surface area by . A container with twice the height, width and length holds 8 times as much, not twice as much.
Missing or extra faces
Total surface area counts every face; lateral area leaves out the bases; an open box has no top. Read which surface is meant, then list the faces in words before adding their areas.
Diameter in a cylinder formula
uses the radius. A cylinder "8 across" has , and using 8 makes the volume four times too large.
Dividing volumes to count objects
Rigid objects fit dimension by dimension. Round each count down, then multiply. The volume ratio is an upper limit, not the answer.
Check yourself
Answer each question before you open its answer.
Question 1: A cube from its surface area
Volume
A cube has a total surface area of . What is its volume?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: C.
Working
Six equal faces share the surface area, so each face is and the edge is . The volume is .
Why the other options are wrong
- A. This is the area of one face, . The volume needs the edge, 4, cubed.
- B. Divides the surface area by 4, as if the cube had only four faces, and stops there.
- D. Takes the volume equal to the surface area. They are different kinds of measure and equal only for a cube of edge 6.
- E. Uses 6, the number of faces, as the edge length: .
What carries over
From a cube's surface area, divide by 6, take the square root for the edge, then cube it.
Question 2: Which cylinder holds more?
Quantitative Comparison
Cylinder has radius and height . Cylinder has radius and height .
Quantity A: the volume of cylinder
Quantity B: the volume of cylinder
- A.Quantity A is greater.
- B.Quantity B is greater.
- C.The two quantities are equal.
- D.The relationship cannot be determined from the information given.
Show the answer
Answer: B. Quantity B is greater.
Working
Volume of : . Volume of : . Since , Quantity B is greater.
Why the other options are wrong
- A. Favours the taller cylinder. Height enters the volume once, but the radius enters squared.
- C. Notices that radius times height is 24 for both. The volume uses radius squared times height, which differs.
- D. Both radii and both heights are given, so both volumes can be computed exactly.
What carries over
In a cylinder the radius counts twice, so a wider cylinder can beat a taller one.
Question 3: Packing a box
Three-dimensional figures
A box has inside dimensions by by . Cubes with edge are packed inside it, with their faces parallel to the box's faces. What is the greatest number of cubes that can fit?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: B.
Working
Along each 9 side, , so 4 cubes fit. Along the 4 side, 2 cubes fit. The greatest number is .
Why the other options are wrong
- A. Counts only one layer of cubes on the floor. The height of 4 holds two layers.
- C. Divides the volumes, , and rounds down. The half-unit gaps along two sides cannot be combined into whole cubes.
- D. Rounds up to 5 along each 9 side. A fifth cube would stick out of the box.
- E. Divides the volume by the edge, , instead of by the cube's volume, .
What carries over
Count rigid objects one dimension at a time, rounding each count down before you multiply.
Key points
Constant cross-section: volume is base area times height.
Surface area is the sum of the faces; list them before adding.
Space diagonal of a box: .
Lengths scale by , areas by , volumes by .
To count objects that fit, round down in each dimension, then multiply.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.