Lesson 33 of 46 · Geometry
Triangles and the Pythagorean theorem
Bound a missing side with the triangle inequality, find areas with the right height, and use the Pythagorean theorem only where it applies.
About 20 minutes
In this lesson
- Use the triangle inequality to find the possible lengths of a third side.
- Find a triangle's area from any base and the height perpendicular to it.
- Apply the Pythagorean theorem and its converse, and recognise the common whole-number right triangles.
- Tell from three side lengths whether a triangle is acute, right or obtuse.
The idea
What every triangle obeys
Three facts hold for every triangle, whatever its shape.
- The angles add to .
- Bigger sides face bigger angles. The longest side is opposite the largest angle, and the shortest side opposite the smallest. Equal sides face equal angles: in an isosceles triangle the two angles at the base are equal, and in an equilateral triangle every angle is .
- The triangle inequality. Each side is shorter than the other two together. If two sides are and with , the third side satisfies
Why strict? If were exactly , the two shorter sides laid end to end would only just reach, and the "triangle" would flatten into a straight segment with no area. Questions that ask how many whole-number lengths are possible depend on getting those two endpoints excluded.
Area: base times height, with the right height
Any side can be the base. The height is the perpendicular distance from the opposite vertex to the line containing that base. In a right triangle the two legs are a base and its height. In an obtuse triangle the height to one of the short sides falls outside the triangle, onto that side extended; the formula still works.
Because one triangle has one area, the three base–height pairs all give the same product. That is a useful tool: once you know the area, you can find the height to any other side by dividing twice the area by that side.
A slanted side is a height only if it is perpendicular to the base. Multiplying two sides that meet at an angle other than gives too large an area.
The Pythagorean theorem
In a right triangle with legs and and hypotenuse (the side opposite the right angle, always the longest side):
The theorem works in both directions. If three sides satisfy , the angle opposite is a right angle. Comparing with (where is the longest side) also sorts every triangle:
| Longest side | The angle opposite is | The triangle is |
|---|---|---|
| less than | acute | |
| exactly | right | |
| more than | obtuse |
The intuition: hold sides and fixed and open the angle between them. The wider the angle, the longer the third side; at exactly it equals .
Whole-number right triangles worth knowing
Some side triples come up because they keep the arithmetic clean. Knowing them saves a square root.
| Triple | Check |
|---|---|
Any multiple of a triple is a triple too: and are both scaled up. Before you square anything, check whether the given sides are a multiple of a known triple. A leg of with a hypotenuse of is doubled, so the other leg is .
Make sure the triple is in the right order. Legs of and do not give a hypotenuse of : the hypotenuse is the longest side, so it would be .
Where right triangles hide
Many questions do not show a right triangle; you build one. A rectangle's diagonal splits it into two right triangles. The height of an isosceles triangle drawn to its base cuts the base in half and makes two right triangles. A distance between two points on a grid is the hypotenuse of a triangle whose legs are the horizontal and vertical gaps. When a length is missing, look for a right angle you can create.
Worked examples
Example 1: How many whole-number third sides?
Two sides of a triangle measure and . If the third side is a whole number, how many lengths are possible?
Apply the triangle inequality: , so .
The whole numbers strictly between 5 and 19 run from 6 to 18.
Count them: .
Answer
There are possible lengths. Including the endpoints 5 and 19 gives the tempting wrong count of 15; both would flatten the triangle into a line.
Example 2: A missing leg, then the area
In right triangle , the right angle is at . The hypotenuse is and leg is . What is the area of the triangle?
The legs are and , because the right angle is at . So .
Spot the triple: and are and doubled, so . Check: .
The two legs are a base and its height: area .
Answer
The area is . Using the hypotenuse as a height, , is the tempting wrong answer; the hypotenuse is not perpendicular to .
Example 3: An isosceles triangle and two heights
Triangle has and . Find its area, and then the height from to side .
Drop the height from to at point . In an isosceles triangle this height meets the base at its midpoint, so and angle is a right angle.
In right triangle : , so (a triangle).
Area .
Now use as the base. The area is still 60, so and .
Answer
The area is and the height from to is . Taking the slanted side as the height, , overstates the area.
Common traps
Pythagoras on a triangle with no right angle
holds only when the angle opposite is . If no right angle is stated or marked, the squares do not add up and you cannot use them to find a side. Look for a right angle you can create instead, such as an altitude.
Treating the missing side as the hypotenuse
Given sides 6 and 10 of a right triangle, the third side is if 10 is the hypotenuse, and only if 6 and 10 are both legs. Read where the right angle is before deciding which side is .
Including the endpoints of the triangle inequality
The third side is strictly between the difference and the sum of the other two. With sides 4 and 9, a third side of 5 or 13 gives a flat figure with no area, not a triangle.
Using a slanted side as the height
The height must be perpendicular to the base. A side that leans is longer than the height it stands in for, so the area comes out too large. If the height is not given, build a right triangle to find it.
Check yourself
Answer each question before you open its answer.
Question 1: A possible perimeter
Triangles
Two sides of a triangle have lengths and . Which of the following could be the perimeter of the triangle?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: C.
Working
The third side satisfies , so . The perimeter is , so it lies strictly between and . Of the options only (third side ) is in that range.
Why the other options are wrong
- A. Would make the third side 5, which is less than ; the two short sides could not meet.
- B. Would make the third side exactly 6, the difference of the other two. The figure would be flat, so the inequality is strict.
- D. Would make the third side exactly 16, the sum of the other two: a flat figure, not a triangle.
- E. Would make the third side 17, longer than ; the other two sides could not reach.
What carries over
Turn a perimeter question into a third-side question, and keep both ends of the inequality strict.
Question 2: Area from a hypotenuse and a leg
The Pythagorean theorem
A right triangle has a hypotenuse of length and one leg of length . What is the area of the triangle?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: A.
Working
The other leg is (an triangle). The legs are perpendicular, so the area is .
Why the other options are wrong
- B. Uses the hypotenuse as the height: . The hypotenuse is not perpendicular to the leg.
- C. Finds the right legs, 8 and 15, but forgets the in the area formula.
- D. Multiplies the other leg by the hypotenuse, ; those two sides are not perpendicular either.
- E. Multiplies the two given sides with no : .
What carries over
In a right triangle the two legs are base and height; find the missing leg first.
Question 3: Acute, right or obtuse?
Quantitative Comparison
A triangle has sides of lengths , and .
Quantity A: the measure of the largest angle of the triangle, in degrees
Quantity B:
- A.Quantity A is greater.
- B.Quantity B is greater.
- C.The two quantities are equal.
- D.The relationship cannot be determined from the information given.
Show the answer
Answer: A. Quantity A is greater.
Working
The largest angle is opposite the longest side, 11. Compare with . Since , the angle opposite 11 is greater than .
Why the other options are wrong
- B. Assumes a triangle with no stated right angle must be acute. Comparing squares shows the largest angle is obtuse.
- C. Treats the triangle as right-angled. That would need , but .
- D. Three side lengths fix a triangle completely, so its angles are determined even though they are not given.
What carries over
Compare the square of the longest side with the sum of the other two squares to classify a triangle without finding any angle.
Key points
The third side lies strictly between the difference and the sum of the other two.
Area is half of base times the height perpendicular to that base; any side can be the base.
only in a right triangle, with the hypotenuse opposite the right angle.
Know ; ; ; and their multiples.
Longest side squared against the sum of the other two squares: less is acute, equal is right, more is obtuse.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.