Lesson 20 of 24 · Mathematics
Solid geometry and changes of scale
Choose a base and perpendicular height, separate exposed area from volume and recover a length scale from an area or volume ratio.
About 20 minutes
In this lesson
- Choose the dimensions needed for a volume.
- Count only the surfaces exposed after joining solids.
- Convert between length, area and volume scale factors.
The idea
Imagine cutting the solid into layers
Place a rectangular box flat on the table. A layer one centimetre thick contains one cubic centimetre for every square centimetre of base. Stacking identical layers gives the volume (volume) as base area times height. Nothing requires the base to be a rectangle. The same argument works for a prism with a triangular end or a cylinder with a circular end. Pick two parallel ends of the same shape and measure the perpendicular separation between them.
A sloping edge can be much longer than that separation. Imagine pushing the top of a stack of cards sideways without changing the thickness of any card. The slanted stack occupies the same volume as the upright one because every horizontal layer still has the same area. If a diagram supplies a sloping length, look for a right triangle containing the perpendicular height before substituting into a formula.
A pyramid or cone tapers to a point. The formula for either is one third of the base area times the perpendicular height. The factor one third already accounts for all the shrinking cross-sections. In particular, halving the height remaining above a cut parallel to the base also halves each lateral dimension of the section there. Its area falls to one quarter. Treating the sections as if their areas decreased at a constant rate would give a different volume.
Decide which faces are on the boundary
Surface area (superficie) counts the material needed for a skin. Imagine painting every accessible face of the finished object. A rectangular box has three pairs of equal faces. Multiplying the two lengths along a face measures one member of a pair. Double the sum of those three different products for a closed box. If the box is open at the top, remove just the missing face.
A cylinder's curved wall unwraps into a rectangle whose long side runs around the rim. Its dimensions are the circumference and the height. Add two circular discs for a closed cylinder or just one for a pot without a lid. For a right circular cone the curved wall uses the slant height instead. The flattened wall is a sector with arc length equal to the base circumference, giving lateral area when the slant height is . This length and the vertical height play different roles.
Scale one, two or three directions
Suppose a manufacturer makes a model with every length three times the corresponding original length. Along a straight edge three small rulers fit where one did before. Across a rectangular face there are three rows of three original rectangles. Inside a box there are three layers of nine original boxes. Accordingly a length factor gives an area factor and a volume factor . Similar curved solids obey the same rules. For a sphere the formulas and display both powers directly.
To reverse the calculation, keep the direction of the ratio visible. A model with one eighth of the volume of a similar full-size object has half its lengths. If the question asks how much longer the original is, turn the ratio around after taking the cube root. Check whether the word “similar” is justified. Doubling just the height of a cylinder with fixed radius doubles its volume. Its curved wall doubles in area while its two ends keep their original areas.
Check the units before comparing
Changing the unit of measurement also applies a scale factor. An edge one metre long has length one hundred centimetres. A square of side one metre contains one hundred rows of one hundred square centimetres. A cubic metre contains one hundred such layers of thickness one centimetre. Convert all lengths to one unit before multiplying them, or convert the final answer with the appropriate square or cube factor. Write the physical unit beside the number even if the options omit it.
Worked examples
Example 1: Height inside a cone
A right circular cone has base radius 3 cm and slant height 5 cm. Find its volume.
A vertical section through the axis gives a right triangle with legs 3 and the unknown height, and hypotenuse 5.
By Pythagoras the height is 4 cm. Multiply the base area by this height and divide by three.
Answer
The volume is cubic centimetres. Using 5 as the vertical height would give .
Example 2: A joined surface
Two identical cubes of edge 3 cm are glued together along one full face each. What area can be painted?
Separate cubes have twelve square faces in total.
The joint hides two faces, leaving ten exposed squares of area 9 square centimetres each.
Answer
The paint covers 90 square centimetres.
Common traps
Counting a seam
A seam can be visible around an edge while the faces meeting inside are hidden. Subtract the contact area twice when adding the surface areas of two closed solids.
Scaling only one dimension
Check the wording for similarity before cubing a length ratio. A container made taller with its base fixed retains its original base area.
Check yourself
Answer each question before you open its answer.
Question 1: Area from volume ratio
Plane and solid geometry
Two similar tanks have volumes in the ratio small to large of 8 to 125. What is their surface area ratio?
- A.2 to 5
- B.4 to 25
- C.8 to 125
- D.25 to 4
- E.16 to 625
Show the answer
Answer: B. 4 to 25
Working
Cube roots give corresponding lengths in the ratio 2 to 5. Squaring gives 4 to 25.
Why the other options are wrong
- A. This is the ratio of corresponding lengths.
- C. This repeats the volume ratio.
- D. This reverses the requested direction.
- E. This squares the area ratio a second time.
What carries over
Take the cube root before converting volume ratios to area ratios.
Question 2: An open cylindrical cup
Plane and solid geometry
A cylinder of radius 2 cm and height 5 cm has a base and an open top. What is its total surface area in square centimetres?
- A.
- B.
- C.
- D.
- E.
Show the answer
Answer: B.
Working
The wall contributes and the base adds . Their sum is .
Why the other options are wrong
- A. This counts only the curved wall.
- C. This adds a lid as well as the base.
- D. This uses half the circumference for the width of the curved wall.
- E. This counts only the base of the cup.
What carries over
Count the circular faces specified in the problem.
Question 3: A square pyramid
Plane and solid geometry
A pyramid has a square base of side 6 m and perpendicular height 4 m. What is its volume in cubic metres?
- A.8
- B.36
- C.48
- D.72
- E.144
Show the answer
Answer: C. 48
Working
The base has area 36 square metres. Multiply by 4 and divide by 3 to get 48 cubic metres.
Why the other options are wrong
- A. This uses the side length in place of the base area.
- B. This gives the base area alone.
- D. This halves the enclosing prism as for a triangular cross-section.
- E. This gives the full prism volume.
What carries over
Tapering to a single apex introduces the factor one third.
Key points
Choose a base and measure its perpendicular height.
Trace the exposed boundary before adding face areas.
Square a length factor for areas and cube it for volumes.
All questions here are original and written for UniExamer; none comes from the test maker.
Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.