Lesson 3 of 35 · Quantitative Reasoning: arithmetic

Fractions, decimals and percents without a calculator

Switch between fractions, decimals and percents, compare fractions fast, handle decimals by hand and chain percent changes correctly.

About 20 minutes

In this lesson

  • Convert between fractions, decimals and percents, choosing whichever makes the arithmetic shortest.
  • Compare and order fractions by cross-multiplying or with benchmarks.
  • Multiply and divide decimals by hand, and tell which fractions terminate.
  • Chain percent changes and fractions of a remainder without adding them.

The idea

One number, three spellings

A fraction, a decimal and a percent are three ways of writing the same value, and without a calculator the right spelling decides how long a question takes. 37.5%37.5\% of 168 is awkward as a decimal and quick as 38\frac{3}{8} of 168. These equivalents are worth knowing without thinking:

Fraction Decimal Percent
13\frac{1}{3}, 23\frac{2}{3} 0.3‾0.\overline{3}, 0.6‾0.\overline{6} 3313%33\frac{1}{3}\%, 6623%66\frac{2}{3}\%
16\frac{1}{6}, 56\frac{5}{6} 0.16‾0.1\overline{6}, 0.83‾0.8\overline{3} 1623%16\frac{2}{3}\%, 8313%83\frac{1}{3}\%
18\frac{1}{8}, 38\frac{3}{8}, 58\frac{5}{8}, 78\frac{7}{8} 0.1250.125, 0.3750.375, 0.6250.625, 0.8750.875 12.5%12.5\%, 37.5%37.5\%, 62.5%62.5\%, 87.5%87.5\%
19\frac{1}{9} 0.1‾0.\overline{1} 1119%11\frac{1}{9}\%
112\frac{1}{12} 0.083‾0.08\overline{3} 813%8\frac{1}{3}\%
120\frac{1}{20}, 125\frac{1}{25} 0.050.05, 0.040.04 5%5\%, 4%4\%

One more swap saves time: x%x\% of yy equals y%y\% of xx, because both are xy100\frac{xy}{100}. So 16%16\% of 75 is 75%75\% of 16, which is 12.

Comparing fractions

To compare ab\frac{a}{b} and cd\frac{c}{d} with positive denominators, cross-multiply: ab>cd\frac{a}{b} > \frac{c}{d} exactly when ad>bcad > bc. This is the same as writing both over the common denominator bdbd, without writing it. Two quicker tools often finish the job first:

  • Benchmarks. 511\frac{5}{11} is below 12\frac{1}{2} and 611\frac{6}{11} is above it, so neither needs arithmetic to be placed against 12\frac{1}{2}.
  • Distance from 1. 78\frac{7}{8} and 910\frac{9}{10} fall short of 1 by 18\frac{1}{8} and 110\frac{1}{10}. The smaller shortfall wins, so 910\frac{9}{10} is larger.

Decimals by hand

To multiply decimals, multiply the digits as whole numbers, then count decimal places. 0.4×0.0250.4 \times 0.025 is 4×25=1004 \times 25 = 100 with 1+3=41 + 3 = 4 places, so 0.0100=0.010.0100 = 0.01. To divide, move both decimal points the same number of places until the divisor is a whole number; this multiplies top and bottom by the same power of ten, so the value does not change: 0.360.009=3609=40\frac{0.36}{0.009} = \frac{360}{9} = 40. When the places get confusing, write each number as digits times a power of ten and add the exponents.

Which fractions terminate?

A fraction in lowest terms has a terminating decimal exactly when its denominator has no prime factors other than 2 and 5. 740\frac{7}{40} terminates, since 40=23×540 = 2^3 \times 5; 730\frac{7}{30} does not, since 30 contains 3. Reduce first: 2156=38=0.375\frac{21}{56} = \frac{3}{8} = 0.375 terminates even though 56 contains 7.

Percents as multipliers

A rise of p%p\% multiplies by 1+p1001 + \frac{p}{100} and a fall of p%p\% by 1−p1001 - \frac{p}{100}. Successive changes multiply, and to undo a change you divide by its multiplier. A percent change is always measured from the value the change starts from:

percent change=new−oldold×100%\text{percent change} = \frac{\text{new} - \text{old}}{\text{old}} \times 100\%

Profit and discount questions are chains of multipliers. A cost marked up 50% and then discounted 20% sells for 1.5×0.8=1.21.5 \times 0.8 = 1.2 times the cost, a profit of 20% of the cost, not the 30% that subtracting the percents suggests.

Fractions of what is left

"Spent 15\frac{1}{5}, then 34\frac{3}{4} of the remainder" takes the second fraction of a smaller amount. Track what is left after each step: 45\frac{4}{5} remains after the first step and 14\frac{1}{4} of that after the second, so 45×14=15\frac{4}{5} \times \frac{1}{4} = \frac{1}{5} of the original remains. Writing the remaining fraction at each step avoids the most common slip, taking every fraction of the original amount.

Estimate before you choose

Answer choices on problem-solving questions are often spread out enough that a rough value picks the right one. Rounding 2961\frac{29}{61} to just under 12\frac{1}{2}, or 0.1980.198 to 0.20.2, is legitimate whenever the options are far apart; when they are close, do the exact arithmetic.

Worked examples

Example 1: Ordering three close fractions

Put 712\frac{7}{12}, 59\frac{5}{9} and 47\frac{4}{7} in order from smallest to largest.

  1. All three are just above 12\frac{1}{2}, so the benchmark does not separate them. Cross-multiply in pairs.

  2. 712\frac{7}{12} against 59\frac{5}{9}: 7×9=637 \times 9 = 63 and 5×12=605 \times 12 = 60, so 712\frac{7}{12} is larger.

  3. 59\frac{5}{9} against 47\frac{4}{7}: 5×7=355 \times 7 = 35 and 4×9=364 \times 9 = 36, so 47\frac{4}{7} is larger.

  4. 712\frac{7}{12} against 47\frac{4}{7}: 7×7=497 \times 7 = 49 and 4×12=484 \times 12 = 48, so 712\frac{7}{12} is larger. Second route: how far each is above 12\frac{1}{2}: 112\frac{1}{12}, 118\frac{1}{18} and 114\frac{1}{14}, which order the same way.

Answer

59<47<712\frac{5}{9} < \frac{4}{7} < \frac{7}{12}. Judging by the size of the denominators alone would have put them in the wrong order.

Example 2: An awkward percent as a fraction

Without a calculator, find 37.5%37.5\% of 168.

  1. Recognise 37.5%=3837.5\% = \frac{3}{8}.

  2. Divide first, then multiply: 168÷8=21168 \div 8 = 21 and 21×3=6321 \times 3 = 63.

  3. Second route: 37.5%=40%−2.5%37.5\% = 40\% - 2.5\%. 40%40\% of 168 is 67.267.2 and 2.5%2.5\% of 168 is 4.24.2, so the result is 67.2−4.2=6367.2 - 4.2 = 63.

Answer

37.5%37.5\% of 168 is 63.

Example 3: A markup followed by a discount

A shop prices an item 40% above its cost, then sells it at 15% off that price. The profit is $19\$19. What did the item cost the shop?

  1. Chain the multipliers: the selling price is c×1.4×0.85=1.19cc \times 1.4 \times 0.85 = 1.19c.

  2. Profit is selling price minus cost: 1.19c−c=0.19c=191.19c - c = 0.19c = 19, so c=100c = 100.

  3. Check forwards: marked price $140\$140, discount 15%15\% of $140\$140 is $21\$21, selling price $119\$119, profit $19\$19.

Answer

The item cost $100\$100. Subtracting the percents (40−15=25%40 - 15 = 25\% profit) gives a cost of $76\$76, which is wrong because the discount is taken of the marked price, not of the cost.

Common traps

  • Taking every fraction of the original

    "A quarter, then two thirds of the rest" is not 14+23\frac{1}{4} + \frac{2}{3} of the whole. The second fraction applies to what remains. Write the fraction left after each step and multiply those.

  • Adding or subtracting successive percents

    A 40% markup and a 15% discount do not net to 25%. The discount is taken of a larger number, so the multipliers 1.41.4 and 0.850.85 must be multiplied. Any time one change follows another, multiply.

  • Losing a decimal place

    Most decimal errors are off by a power of ten, and the answer choices often include the neighbours 33, 3030 and 300300. Count decimal places deliberately, or rewrite numbers as digits times powers of ten, and estimate the size of the answer before choosing.

  • Judging a decimal before reducing

    Whether a fraction terminates depends on the denominator in lowest terms. 2156\frac{21}{56} looks as if the 7 in 56 should stop it terminating, but it reduces to 38\frac{3}{8}. Cancel common factors first.

Check yourself

Answer each question before you open its answer.

Question 1: The fall that follows a rise

Problem Solving

An investment's value rose 25% during its first year. At the end of the second year it was worth 10% less than at the start of the first year. By what percent did its value fall during the second year?

  1. A.10%
  2. B.20%
  3. C.25%
  4. D.28%
  5. E.35%
Show the answer

Answer: D. 28%

Working

Start at 100. After the first year the value is 125; at the end of the second year it is 90. The second-year fall is 125−90125=35125=0.28\frac{125 - 90}{125} = \frac{35}{125} = 0.28, or 28%. With multipliers: 0.91.25=0.72\frac{0.9}{1.25} = 0.72, a fall of 28%.

Why the other options are wrong

  • A. 10% is the overall change across both years, not the fall during the second year.
  • B. A 20% fall only undoes the 25% rise and returns the value to its start; it has to fall further, to 10% below the start.
  • C. A fall equal to the rise gives 1.25×0.75=0.93751.25 \times 0.75 = 0.9375, about 6% below the start rather than 10%.
  • E. The value drops 35 for every 100 of the original amount, but the second year's percent change is measured from the 125 it started that year with.

What carries over

Measure each period's percent change from the value at the start of that period.

Question 2: Decimals by hand

Problem Solving

0.6×0.0350.0007=  ?\frac{0.6 \times 0.035}{0.0007} = \;?

  1. A.3
  2. B.30
  3. C.300
  4. D.3,000
  5. E.30,000
Show the answer

Answer: B. 30

Working

Numerator: 6×35=2106 \times 35 = 210 with 4 decimal places, so 0.0210=0.0210.0210 = 0.021. Divide: 0.0210.0007=2107=30\frac{0.021}{0.0007} = \frac{210}{7} = 30 after moving both decimal points four places. With powers of ten: 6×10−1×35×10−37×10−4=210×10−47×10−4=30\frac{6 \times 10^{-1} \times 35 \times 10^{-3}}{7 \times 10^{-4}} = \frac{210 \times 10^{-4}}{7 \times 10^{-4}} = 30.

Why the other options are wrong

  • A. This takes the numerator as 0.00210.0021; the product 0.6×0.0350.6 \times 0.035 has 1+3=41 + 3 = 4 decimal places and equals 0.02100.0210.
  • C. This takes the numerator as 0.210.21, one decimal place short of the correct 0.0210.021.
  • D. This takes the numerator as 2.12.1, losing two decimal places of the product.
  • E. This treats 0.6×0.0350.6 \times 0.035 as the whole number 21, dropping every decimal place of the product.

What carries over

Count decimal places on purpose, or convert to powers of ten, before you divide.

Question 3: Savings spent in two steps

Problem Solving

Rosa spent 14\frac{1}{4} of her savings on a laptop and then 23\frac{2}{3} of the remaining savings on a trip. She has $600\$600 left. How much were her savings at first?

  1. A.$1,200
  2. B.$1,800
  3. C.$2,400
  4. D.$3,600
  5. E.$7,200
Show the answer

Answer: C. $2,400

Working

After the laptop 34\frac{3}{4} of the savings remain; after the trip 13\frac{1}{3} of that remains, so 34×13=14\frac{3}{4} \times \frac{1}{3} = \frac{1}{4} of the savings is $600\$600, and the savings were $2,400\$2,400. Forwards: the laptop costs $600\$600, leaving $1,800\$1,800; the trip costs 23×1800=$1,200\frac{2}{3} \times 1800 = \$1,200, leaving $600\$600.

Why the other options are wrong

  • A. This treats 23\frac{2}{3} as the share left after the trip rather than the share spent on it.
  • B. $600\$600 is a third of $1,800\$1,800, but $1,800\$1,800 is what remained after the laptop, not the starting savings.
  • D. This multiplies the two spent fractions, 14×23=16\frac{1}{4} \times \frac{2}{3} = \frac{1}{6}, and treats that as what is left.
  • E. This takes both fractions of the original savings: 14+23=1112\frac{1}{4} + \frac{2}{3} = \frac{11}{12} spent, leaving 112\frac{1}{12}.

What carries over

Multiply the fractions that remain after each step, not the fractions spent.

Key points

  • Pick the spelling that makes the arithmetic short: fraction, decimal or percent.

  • Cross-multiply to compare fractions; use benchmarks and the distance from 1 first.

  • Count decimal places deliberately, or use powers of ten.

  • Successive percent changes and fractions of a remainder multiply; they never add.

All questions here are original and written for UniExamer; none comes from the test maker.

Written by the UniExamer team with AI assistance. Every worked example and check question was re-solved by an independent checker before publication. No subject expert has reviewed this lesson yet. If you find a mistake, write to support@uniexamer.com.

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